[UPSC CSE ] Nuclear Physics (Q102, 10M)

Calculate the Q-value of the reaction: {}^{9}_{4}\mathrm{Be}({}^{4}_{2}\mathrm{He},\mathrm{n}){}^{12}_{6}\mathrm{C} Given: \begin{aligned} \text{Mass }({}^{9}_{4}\mathrm{Be}) &= 9.01283\,\mathrm{u}\\ \text{Mass }({}^{4}_{2}\mathrm{He}) &= 4.002603\,\mathrm{u}\\ \text{Mass }({}^{12}_{6}\mathrm{C}) &= 12.000\,\mathrm{u}\\ \text{Mass }(\mathrm{n}) &= 1.0086652\,\mathrm{u} \end{aligned}